for(i=a-1,j=1;i>=0&&i for(a=m;a if(a%2!=0) {c[0][a]=c[0][a-1]+1; for(i=1,j=a-1;i>=0&&i {c[m-1][a+1-m]=c[m-1][a-m]+1; for(i=m-2,j=a+2-m;i>=0&&i for(a=n;a<=m+n-2;a++) { if(a%2!=0) {c[a+1-n][n-1]=c[a-n][n-1]+1; for(i=a+2-n,j=n-2;i>=0&&i {c[m-1][a+1-m]=c[m-1][a-m]+1; for(i=m-2,j=a+2-m;i>=0&&i if(s==1) {for(i=0;i for(j=0;j for(j=0;j printf(\ \ putchar('\\n'); } } else for(i=0;i for(j=0;j printf(\ \ putchar('\\n');} } #include ”stdio.h” #define N 5 int main() { int a[N][N]; int i,j,m=0,n=0; int count=1; for(i=1;i<=N;i++) for(j=1;j<=i;j++) { a[m][n]=count; if(i%2==0) { m++; n--; if(n<0) n=0; } else {m--; n++; if(m<0) m=0; } count++; } m=1;n=N-1; for(i=N-1;i>=1;i--) for(j=i;j>=1;j--) { a[m][n]=count; if(i%2==0) { m++; n--; if(m>N-1) {n+=2; m=N-1; } } else {m--;n++; if(n>N-1) { m+=2; n=N-1; } } count++; } for(i=0;i printf(\ if(j==N-1) printf(\ } system(\ return 0; } #include int i,j,N,c; scanf(\ for (i=1;i<=N;i++) for (j=1;j<=N;j++) { if (j>=i&&j<=N+1-i||j<=i&&j>=N+1-i) if (i<=(N+1)/2) c=(i-1)*(4*N-4*i+3)+j; else c=2*(N-i)*(2*i-1)+3*i-j-1; else if (j<=(N+1)/2) c=4*N*j-4*j*j-i+j+1; else c=(N-j)*(4*j-3)+N+i-1; printf((j==N)?\ } system(\ }
北理工C语言编程网上作业答案(6)
2025-07-27
北理工C语言编程网上作业答案(6).doc
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