i=n/2;
printf("%d\n",i);}
}
return 0;
}
18·二分求根
#include<math.h>
#include<stdio.h>
double fun(double x) {return 2*x*x*x-4*x*x+3*x-6;} double root(double a,double b,double e)
{
double x1,x2,y1,x,y;
x1=a;
x2=b;
do {
x=(x1 + x2)/2;
y=fun(x);
y1=fun(x1);
if((y<0&&y1<0)||(y>0&&y1>0))
x1=x;
else
